MID Function

lehy2002

New Member
Joined
Nov 3, 2016
Messages
22
HI! I am fairly familiar with excel but I am really having a problem with the calculations below. The Approval History is formatted as General, the Closed as Custom but no matter what I do with formatting it won't fix the error. One thing that did work is adding the text, even just the " - Group approval" part (no quotations) and it will work. I think I used to know this but I am stumped on why this is happening. Other question is, what is the purpose of the 2 hyphens in front of MID. (I think I know but I am not sure so I am asking.) Thank you so much and the quicker I can get an answer the better. I will be watching for responses.


Approval HistoryClosedFunction Approval HxFunction Closed
03/22/2018 08:49:02 AM - Group approval for Gatekeeper approved by user Angl Hoo (Group Approval).


3/23/2018 12:35:04 PM
43181

<tbody>
</tbody>
#VALUE!

<tbody>
</tbody>
IF(ISBLANK(E2),"",IF(ISERROR(--MID(E2,FIND("/",E2)-2,10)),--MID(E2,FIND("/",E2)-1,9),--MID(E2,FIND("/",E2)-2,10)))IF(ISBLANK(E2),"",IF(ISERROR(--MID(E2,FIND("/",E2)-2,10)),--MID(E2,FIND("/",E2)-1,9),--MID(E2,FIND("/",E2)-2,10)))

<tbody>
</tbody>
 

Excel Facts

Did you know Excel offers Filter by Selection?
Add the AutoFilter icon to the Quick Access Toolbar. Select a cell containing Apple, click AutoFilter, and you will get all rows with Apple
It would seem the value under 'Closed' is a real date value. Which is actually a numeric value, cell formatting makes it look like a date.
So the FIND function is not going to find a / character, resulting in the #Value ! Error.

Adding any text values to it makes it a TEXT string.

The -- converts a number stored as text to a real number.
The result of MID functions will not be a real number, just a text string.
 
Upvote 0
Thank you - I think that is working. I will round up on the time column that I needed. For future though, how would I get rid of the times on the time/dates so instead of getting a time frame of like 2/19/2018 11:34:06 AM minus 2/15/2018 equals 3.65 and just 2/19/18 minus 2/15/18 I would just get 4 days? Thanks again! (The formatting doesn't change it. It might look like it but we both know it doesn't for real). :)
 
Upvote 0
The INT function will remove the time value.

DATES are the whole number, incrementing by 1 since Jan 1 1900
TIME is the decimal, 6AM = .25, NOON - .5, 6PM = .75 etc...

3.25 = Jan 3 1900 6AM


The INT function strips off the decimal(time) value.
 
Upvote 0

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