An IF statements that operates if a cell CONTAINS any one of a LIST of words...

DrPhilBurns

New Member
Joined
Sep 16, 2015
Messages
5
[FONT=&quot]I know how to write an IF statement that looks at a string of text, and will perform an action if the string CONTAINS a certain "word" using
[/FONT]
[FONT=&quot]=IF(ISNUMBER(SEARCH("*word*",A1)),"word","")
[/FONT]
[FONT=&quot]
[/FONT]
[FONT=&quot]But
Is it possible to write an IF statement that looks at a string of text, and will perform an action if the string CONTAINS any one of a list of certain words?
e.g.
[/FONT]
[FONT=&quot]I have a list of addressess which include the country. I want to do something based on whether the address is in Europe
using similar notation as above, I need something like:
[/FONT]
[FONT=&quot] =IF(ISNUMBER(SEARCH("*
  • *",A1)),"europe","")
    where LIST is a range of cells containing all the European countries "France, Germany, Denmark, ...."[/FONT]
 

Excel Facts

Lock one reference in a formula
Need 1 part of a formula to always point to the same range? use $ signs: $V$2:$Z$99 will always point to V2:Z99, even after copying
Try to describe a problem in words instead of a possible, non-working solution.

Guessing at your problem, try:

=LOOKUP(9.99999999999999E+307,SEARCH(" "&EuropeList&" "," "&A1&" "),EuropeList)
 
Upvote 0
I have figured out the first part of my problem using the formula (which works):
=IF(SUMPRODUCT(--ISNUMBER(SEARCH(Europe,J8))),"Europe","NOT")
where "Europe" is a named list including all the European countries - this returns "Europe" if the address contains a country in the list and "Not" if not.


Next question is:
Is it possible to take the above solution one step further and return the actual matched country from the address?
e.g. if the address contains "France", then the formula returns "France" and so on for each country in the named list Europe?
 
Upvote 0
I have figured out the first part of my problem using the formula (which works):
=IF(SUMPRODUCT(--ISNUMBER(SEARCH(Europe,J8))),"Europe","NOT")
where "Europe" is a named list including all the European countries - this returns "Europe" if the address contains a country in the list and "Not" if not.


Next question is:
Is it possible to take the above solution one step further and return the actual matched country from the address?
e.g. if the address contains "France", then the formula returns "France" and so on for each country in the named list Europe?

See post #2 ...
 
Upvote 0

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