using macro to open a csv file with a file name that changes

tuckercs

New Member
Joined
Mar 1, 2019
Messages
3
I am trying create a macro that will open a .csv file. The file name changes daily. The file name is YYYYMMDD_7dat.csv. Is there a formula that I can put in VBA that will format the open from to this format?
 

Excel Facts

What is the shortcut key for Format Selection?
Ctrl+1 (the number one) will open the Format dialog for whatever is selected.
To specify the current date's file:
Code:
"C:\path\to\folder\" & Format(Date, "YYYYMMDD") & "_7dat.csv"
 
Upvote 0
Here is a copy of the macro I am trying to run. All the red text is the text I need to adjust with the current date.
Sub Transfer()
'
' Transfer Macro
'


'
ActiveWorkbook.Queries.Add Name:="20190304_7dat", Formula:= _
"let" & Chr(13) & "" & Chr(10) & " Source = Csv.Document(File.Contents(""C:\Users\C Tuck\Documents\DATREPORTS\20190304_7dat.csv""),[Delimiter="","", Columns=3, Encoding=65001, QuoteStyle=QuoteStyle.None])," & Chr(13) & "" & Chr(10) & " #""Promoted Headers"" = Table.PromoteHeaders(Source, [PromoteAllScalars=true])," & Chr(13) & "" & Chr(10) & " #""Changed Type"" = Table.TransformColumnTypes(#""Promoted Headers"",{{""SKU"", type text}, {""Qty" & _
" Sold"", Int64.Type}, {""ASIN"", type text}})" & Chr(13) & "" & Chr(10) & "in" & Chr(13) & "" & Chr(10) & " #""Changed Type"""
ActiveWorkbook.Worksheets.Add
With ActiveSheet.ListObjects.Add(SourceType:=0, Source:= _
"OLEDB;Provider=Microsoft.Mashup.OleDb.1;Data Source=$Workbook$;Location=20190304_7dat;Extended Properties=""""" _
, Destination:=Range("$A$1")).QueryTable
.CommandType = xlCmdSql
.CommandText = Array("SELECT * FROM [20190304_7dat]")
.RowNumbers = False
.FillAdjacentFormulas = False
.PreserveFormatting = True
.RefreshOnFileOpen = False
.BackgroundQuery = True
.RefreshStyle = xlInsertDeleteCells
.SavePassword = False
.SaveData = True
.AdjustColumnWidth = True
.RefreshPeriod = 0
.PreserveColumnInfo = True
.ListObject.DisplayName = "_20190304_7dat"
.Refresh BackgroundQuery:=False
End With
End Sub

What would I need to substitute for this in the macro.

Thanks in advance.
 
Upvote 0

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