Array formula with IF criteria

datamster

Board Regular
Joined
Jan 25, 2016
Messages
58
Hello, would anyone be able to assist with an Array formula I'm working on where I'm looking to have it return only the cell in a row matching my criteria. The data starts in row 9 and row 8 is the header.

Code:
{=IFERROR(INDEX(Data!$Y$9:$Y$561,SMALL(IF(Data!$Y$9:$Y$561>=Data!$Z$3,ROW(Data!$C$9:$C$561)-ROW(Data!D$9)),ROWS(Data!Y$9:Data!Y10))),"")}

I have a table with duration values in column Y with the criteria in cell Z3. This formula currently returns the correct column but the criteria part isn't working correctly. If I remove that part and keep the rest as:

Code:
{=IFERROR(INDEX(Data!$C$9:$C$561,SMALL(IF(Data!$Y$9:$Y$561,ROW(Data!$C$9:$C$561)-ROW(Data!C$9)),ROWS(Data!C$9:Data!C10))),"")}

Then it starts populating with the first row.

thank you for any help!
 

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What happens if you change the formula to:

Code:
{=IFERROR(INDEX(Data!$Y$9:$Y$561,SMALL(IF(Data!$Y$9:$Y$561>=Data!$Z$3,ROW(Data!$C$9:$C$561)-ROW(Data!D$9)[B][COLOR=#ff0000]+1[/COLOR][/B]),ROWS(Data!Y$9:Data!Y10))),"")}
 
Upvote 0
Thanks for the quick reply. Almost there I think! Your change returns the correct row for matching criteria but it skipped the first matched row with 3 of 4 showing correctly.
 
Upvote 0
Thanks for the quick reply. Almost there I think! Your change returns the correct row for matching criteria but it skipped the first matched row with 3 of 4 showing correctly.

Maybe this fix it
Code:
=IFERROR(INDEX(Data!$Y$9:$Y$561,SMALL(IF(Data!$Y$9:$Y$561>=Data!$Z$3,ROW(Data!$C$9:$C$561)-ROW(Data!D$9)[B][COLOR=#ff0000]+1[/COLOR][/B]),ROWS([B][COLOR=#ff0000]Data!Y$9:Y9[/COLOR][/B]))),"")

M.
 
Upvote 0

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